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Rows 2-8 of the pattern reads chain 1, stitch increase evenly 6 times around (48 st). Can you tell me exactly how this is done? Thanks.
Chain 1, then increase by working 2 single crochets in the one stitch evenly around the row. Work so many sc (single crochets), then work 2 sc in another stitch to increase.
If you haven't figured this out yet, try this. I'll assume you're doing SC but if not, change to DC.
Ch1
Make 2 SC in first SC of previous row.
SC in next 6
Make 2 SC in next
SC in next 6
(Continue until you've done 2 SC in 6 stitches in that row)
Now, you've increased six stitches over your original 42 stitches and you're ending with 48.
In your next row, row 3, you'll have to increase another 6 stitches spreading them out over the 48 stitches. You'll end with 54 stitches this time.
Do increase rows for a total of 7 rows. You will have 84 stitches (if my math is correct) when you're finished with rows 2-8.
I hope this helps.
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I am making a doily and the pattern says to ch 4 (counts as 1 tr), 2 tr over same ch 3, ch3, a 6-jointed-tr over remainder of this ch 3 and ch 3 of next shell. What is a 6-jointed-tr and how do you make it?
By Julie
